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題目概要：
計算出可以喝多少瓶汽水。e=目前手上的空瓶，f=撿到的空瓶，c=需要幾瓶空瓶換一罐汽水。
解題方向：
1. 可以換的汽水數量=所有空瓶數/c。
2. 手上空瓶=所有空瓶數/c+所有空瓶數%c。
程式碼：
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| //Java | |
| import java.util.Scanner; | |
| class uva11689{ | |
| public static void main(String args[]){ | |
| Scanner sc=new Scanner(System.in); | |
| int cases=sc.nextInt(); | |
| for(int i=0;i<cases;i++){ | |
| int e=sc.nextInt(),f=sc.nextInt(),c=sc.nextInt(); | |
| int total=e+f,count=0; | |
| while((total/c)!=0){ | |
| count=count+total/c; //共喝多少罐汽水 | |
| total=total/c+total%c; //手上剩下的瓶子 | |
| } | |
| //Output | |
| System.out.println(count); | |
| } | |
| } | |
| } |
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