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題目概要：
找出總共轉幾度。
解題方向：
就依照題目給的算法去算即可，只不過都順時針轉時，數字會是0,39,38,37...，逆時針轉時數字會是0,1,2,3,4...。
程式碼：
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| //Java | |
| import java.util.Scanner; | |
| class uva10550{ | |
| public static void main(String args[]){ | |
| Scanner sc=new Scanner(System.in); | |
| while(sc.hasNext()){ | |
| int a=sc.nextInt(),b=sc.nextInt(),c=sc.nextInt(),d=sc.nextInt(); | |
| if(a==0 && b==0 && c==0 && d==0) break; | |
| int degree=1080; //第一步驟、第三步驟所轉的圈數。 | |
| degree+=(a>=b)?(a-b)*9:(40+a-b)*9; //第二步驟 | |
| degree+=(b<=c)?(c-b)*9:(40+c-b)*9; //第四步驟 | |
| degree+=(c>=d)?(c-d)*9:(40+c-d)*9; //第五步驟 | |
| //Output | |
| System.out.println(degree); | |
| } | |
| } | |
| } |
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