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題目概要：
給定一數字，將此數字以10進位來看，並找出轉2進位後共有多少個1，以及16進位來看，轉2進位後共有多少個1。
解題方向：
依計概所教的方法去求出2進位，並計算有多少個1。
程式碼：
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| //Java | |
| import java.util.Scanner; | |
| class main{ | |
| public static void main(String args[]){ | |
| Scanner sc=new Scanner(System.in); | |
| int cases=sc.nextInt(); //多少case需要被處理。 | |
| while((cases--)>0){ | |
| int n=sc.nextInt(); | |
| //Output。 | |
| System.out.println(base10(n)+" "+base16(n)); | |
| } | |
| } | |
| //10進位轉2進位，並回傳有多少個1。 | |
| public static int base10(int n){ | |
| int count=0; | |
| while(n>0){ | |
| if(n%2==1) count++; | |
| n/=2; | |
| } | |
| return count; | |
| } | |
| //16進位轉2進位，並回傳有多少個1。 | |
| public static int base16(int n){ | |
| int count=0; | |
| while(n>0){ | |
| int temp=n%10; | |
| n/=10; | |
| while(temp>0){ | |
| if(temp%2==1) count++; | |
| temp/=2; | |
| } | |
| } | |
| return count; | |
| } | |
| } |
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