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題目概要：
計算出Mario往上跳幾次，往下跳幾次。
解題方向：
比較每個牆壁的大小，左邊的牆壁大於右邊牆壁=往下跳，左邊牆壁小於右邊牆壁=往上跳。
程式碼：
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| //Java | |
| import java.util.Scanner; | |
| class uva11764{ | |
| public static void main(String args[]){ | |
| Scanner sc=new Scanner(System.in); | |
| int total=sc.nextInt(); | |
| for(int i=0;i<total;i++){ | |
| int N=sc.nextInt(); | |
| int wall[]=new int[N]; | |
| for(int j=0;j<N;j++){ | |
| wall[j]=sc.nextInt(); | |
| } | |
| int highJ=0; | |
| int lowJ=0; | |
| for(int j=0;j<N-1;j++){ | |
| if(wall[j]<wall[j+1]) highJ++; | |
| if(wall[j]>wall[j+1]) lowJ++; | |
| } | |
| System.out.println("Case "+(i+1)+": "+highJ+" "+lowJ); | |
| } | |
| } | |
| } |
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