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題目概要：
如果是9的倍數，請找出degree為多少。
解題方向：
1. 輸入的數字有1000位數，所以無法用數字處理，需要用字串。
2. 設輸入數字為999，則degree為2。
(1)9+9+9=27
(2)2+7=9
程式碼：
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| //Java | |
| import java.util.Scanner; | |
| class uva10922{ | |
| public static void main(String args[]){ | |
| Scanner sc=new Scanner(System.in); | |
| while(sc.hasNext()){ | |
| String st=sc.next(); | |
| //當輸入為0時終止程式。 | |
| if(st.equals("0"))break; | |
| /* | |
| 計算有多少degree(9倍數判斷方法：全部數字相加為9倍數)。 | |
| Ex 999 degree=2 | |
| 1. 9+9+9=27 | |
| 2. 2+7=9 | |
| */ | |
| int count=0; | |
| String temp=st; | |
| while(true){ | |
| int total=0; | |
| for(int i=0;i<temp.length();i++){ | |
| total=total+temp.charAt(i)-48; | |
| } | |
| if(total%9==0){ | |
| count++; | |
| if(total==9) break; | |
| else temp=Integer.toString(total); | |
| }else{ | |
| break; | |
| } | |
| } | |
| //結果輸出。 | |
| if(count!=0) System.out.println(st+" is a multiple of 9 and has 9-degree "+count+"."); | |
| else System.out.println(st+" is not a multiple of 9."); | |
| } | |
| } | |
| } |
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